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2/49x^-2+14x=0
Domain of the equation: 49x^!=0We add all the numbers together, and all the variables
x!=0/49
x!=0
x∈R
14x+2/49x^-2=0
We multiply all the terms by the denominator
14x*49x^-2*49x^+2=0
Wy multiply elements
686x^2-98x+2=0
a = 686; b = -98; c = +2;
Δ = b2-4ac
Δ = -982-4·686·2
Δ = 4116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4116}=\sqrt{196*21}=\sqrt{196}*\sqrt{21}=14\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-98)-14\sqrt{21}}{2*686}=\frac{98-14\sqrt{21}}{1372} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-98)+14\sqrt{21}}{2*686}=\frac{98+14\sqrt{21}}{1372} $
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